In this post I would like to discuss
some of the fundamental ideas that can be used to solve number of
trailing zeros in a product important for CAT,E LITMUS,PLACEMENTS,GMAT,GRE/SSC
CGL tier 2. If you have just started your preparation you might find this
article helpful.first of all we should have idea about number of trailing zeros trailing
zeros are a sequence of 0s after which no other digits follow.
think number 210 have one trailing
zeros but have you ever thought why in this number only one trailing zero
because 210 can be written as in form of prime factors
2 × 5 × 3 × 7 = 210 only one pair of
2 and 5 so there is only there is only one zero at the end of the product
so number of trailing zeros depends upon number of pairs of 2’s and 5’s
or We can say that for n number of zero’s at the end of the product we need exactly
n combinations of “5 × 2 “. For example
Again 2 × 3 × 5 × 6 × 7 × 15 = 2 × 3
× 5 × 2 × 3 × 7 × 3 × 5
= 2 × 5× 2 × 5 ×
3 × 3 × 3 × 7
= 100 × 189 = 18900
Thus there are two zeros because
there are two combinations of “5 × 2 “.
Now, 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 ×
9
= 1 × 2 × 3 × 2 × 2 × 5 × 2 × 3 × 7
× 2 × 2 × 2 × 3 × 3
= 1 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 5
× 3 × 3 × 3 × 3 × 7
= 1 × 27 × 5 × 34 × 7
= 1 × 26 × 2 × 5 × 34 × 7
= 10 × 26 × 34 × 7
= 10 × 64 × 81 × 7
= 10 × 36288 = 362880
Thus there is only one zero at the
end of the product since there is only one combination of 5 × 2.
Again 4 × 125 × 3 = 2 × 2 × 5 × 5 ×
5 × 3
= 22 × 53 × 3
= 2 × 5× 2 × 5 × 5 × 3
= 100 × 15 = 1500 Thus
there are only two zeros at the end of the product since there is only one
combination of “5 × 2”.
some CAT/ELITMUS /GRE /GMAT/SSC
CGL MAINS RELATED QUESTIONS
Find the number of trailing
zeros in 55×1010×1515×2020×2525×3030
(a)
130 (b) 80
(c) 100
(d) None
think why answer is 80 since there is only 80
combinations of “5 × 2”.
Find the number of trailing zeros in 11×22×33×44------------100100
(a)
1500
(b)
1350 (c) 1300
(d) 1050
click on this video for solution this question
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