IMPORTANT FOR CAT/PLACEMENTS

     Seventy percent of the employees in a multinational corporation have VCD players, 75 percent have microwave ovens ,80 percents have Acs and 85 percent have washing machines .At least what percent of employees has all four gadgets ?

solution

The least percentage of people with all 4 gadgets would happen if all the employees who are not having any one of the four objects is mutually exclusive thus 100-30-25-20-15=10

Let us call the people P1, P2, P3... P100

P = 30 people don't have VCD. Let them be P1, P2.. P30

Q = 25 people don't have ovens. Let them be P31, P32, P33... P55

R = 20 people don't have ACs. Let them be P56, P57, P58... P75.

S = 15 people don't have Washing Machines. Let them be P76, P77... P90.

Now, P91, P92... P100 have everything. So, 10 people have everything.

If you make some people common in P, Q, R, and S; then the number of people who have everything will be more that 10.

=> The minimum number of people who have everything is 10.